Completing the Square???

[cOOkIe_mOnStEr]

How would you do that? I tried to complete the square but i don't know and I just get confused even more.

 

[pka]

This is equivalent to: 2x<SUP>2</SUP>−3x−7=0.

 

[cOOkIe_mOnStEr]

Yeah, I got that far, but you can't simplify it further can you? I've tried to complete the square on it but it doesnt seem too clear to me. By using the quadratic equation, I got...

Is that right? That's what I got.

 

[TchrWill]

Given x^2 + 10x - 4 = 0.
Transfer the -4 to the other side yielding x^2 + 10x = 4.
Add the square of 1/2 the coefficient of x to both sides yielding x^2 + 10x + 25 = 29.
Then, (x + 5)^2 = 29 or x + 5 = +/-sqrt29 or x = -5 +/- sqrt29.

Using the quadratic equation
x^2 + 10x - 4 = 0.
Therefore, x = [-10+/-sqrt100 + =16)]/2 or
= [-10+/-2sqrt29)]/2 or x = -5 +/-sqrt29.

Given 4x^2 + 4x -11
.........4x^2 + 4x = 11
Divide through by the coefficient of x^2
..........x^2 + x = 11/4
Add the square of 1/2 the coefficient of x to both sides
..........x^2 + x + 1/4 = 11/4 + 1/4 = 12/4 = 3
..........(x + 1/2)^2 = 3
...........x + 1/2 = +/-3
...........x = -1/2 +/-3