Completing the square to solve 3x^2 + 7x = -9

yoda

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Nov 12, 2006
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Solve by completing the square:

. . .3x^2 + 7x = -9

My teacher gave me the answer but I can't figure out how she got it. When I went in to talk to her, I just got more confused. Can someone please help me figure out how to solve by completing the square?

Thank you!
 
Here's an equation to use when completing the square. Your teacher probably wants you to go through the steps, though. The leading coefficient of 3 must be accounted for.

You have \(\displaystyle \L\\\underbrace{3}_{\text{a}}x^{2}+\underbrace{7}_{\text{b}}x+\underbrace{9}_{\text{c}}\)

\(\displaystyle \L\\a(x+\frac{b}{2a})^{2}+\underbrace{c-\frac{b^{2}}{4a}}_{\text{constant}}\)
 
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