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H hazelton17 New member Joined Jan 5, 2009 Messages 1 Jan 5, 2009 #1 asdddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
R royhaas Full Member Joined Dec 14, 2005 Messages 832 Jan 5, 2009 #2 Let X=F−B\displaystyle X=F-BX=F−B. Then X\displaystyle XX has a normal distribution with mean μ(F)−μ(B)\displaystyle \mu(F)-\mu(B)μ(F)−μ(B) and variance σ2(F)+σ2(B)\displaystyle \sigma^2(F)+\sigma^2(B)σ2(F)+σ2(B).
Let X=F−B\displaystyle X=F-BX=F−B. Then X\displaystyle XX has a normal distribution with mean μ(F)−μ(B)\displaystyle \mu(F)-\mu(B)μ(F)−μ(B) and variance σ2(F)+σ2(B)\displaystyle \sigma^2(F)+\sigma^2(B)σ2(F)+σ2(B).
