combining like terms

[ski06]

is 4x+3-2(5+x)=4x+3+-2(5+x)

I am getting different answers but shouldn't you be able to include the sign in front of the number when distributing?

 

[Deleted member 4993]

is 4x+3-2(5+x)=4x+3+-2(5+x)

I am getting different answers but shouldn't you be able to include the sign in front of the number when distributing?

4x+3-2(5+x)=4x+3+-2(5+x)

distribute -2 for multiplication

= 4x + 3 + [-2*5 + (-2)*x]

= 4x + 3 + [-10 + (-2x)]

= 4x + 3 + [-10 -2x]

= 4x + 3 - 10 - 2x

= 4x - 2x + 3 - 10

= 2x - 7

 

[TeacherSatya]

Solution

Alright here we go:

4x+3-2(5+x)=4x+3+-2(5+x) >>> Using distributive property we will break the brackets a(b+c) = ab + ac, a(b-c) = ab - ac, -a(b+c) = -ab - ac

Solution >> 4x + 3 - 10 - 2x = 4x + 3 + (-10 - 2x)
2x - 7 = 4x + 3 - 10 - 2x
2x - 7 = 2x - 7

Hope it helps.

 

[lookagain]

is 4x+3-2(5+x)=4x+3+-2(5+x)

I am getting different answers but shouldn't you be able to include the sign in front of the number when distributing?

ski06, you should not have been given that form.

Because adding a negative is the same as subtracting a positive, you should just have been given:

4x + 3 - 2(5 + x) = 4x + 3 - 2(5 + x)

 

[HallsofIvy]

is 4x+3-2(5+x)=4x+3+-2(5+x)

I wouldn't write "+-", it looks silly to me. I would write either "4x+ 3+ (-2(5+ x))" or "4x+ 3+ (-2)(5+ x)".

In either case, the "-" is as much a part of the number "-2" as the "2" is!