Combinatorics

bbmath

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Feb 7, 2011
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Hello all!

I am new to the forum, but I am in desperate need of help. I am new in a combinatorics class, and I'm needing a little help getting the ball rolling on some proofs.

The first problem asks for a proof by induction. Show that the number of n-letter words that can be formed from letters a,b,c, and d when the letter d occurs an odd number of times is 1/2(4^n-2^n).

I know I need to proceed by weak mathematical induction. I can establish the base case, but when I go into the induction step, I get stuck after defining what an odd number is. Any suggestions?

My other question is how to distribute 17 identical objects into 5 separate boxes if the number of objects in the 1st box is a multiple of 4?

I figure there will be 5 cases each with a multiple of 4 in the first box. (0,4,8,12,16) Then after establishing the 5 cases, it is as simple as figuring out the count of the other 4 boxes within each case.

Does this sound right?

Any help anyone can provide is greatly appreciated!
 
Hello, bbmath!

Welcome aboard!

Here's some help with the second problem.


How to distribute 17 identical objects into 5 separate boxes if the number of objects in the 1st box is a multiple of 4?

I figure there will be 5 cases each with a multiple of 4 in the first box: (0,4,8,12,16).
Then, after establishing the 5 cases, it is as simple as figuring out the count of the other 4 boxes within each case.

Does this sound right? . Yes!

"Figuring out the count of the other 4 boxes" may not be a simple as we would like.
. . I have an approach to this.

I'll consider one case only . . . You can work out the others.


Suppose there 8 objects in the first box.
Then the other 9 objects are distributed among the other four boxes.
How many ways are there?

Place the 9 objects in a row, leaving a space before, after and between them.
. . \(\displaystyle \_\;\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\,\circ\,\_\)

We will place 3 "dividers" in the 10 spaces.
. . Each division represents a distribution of the 9 objects.


Examples:

. . \(\displaystyle \circ\,|\,\circ\,\circ\,|\,\circ\,\circ\,\circ\,\circ\,|\,\circ\,\circ\:\text{ represents }[1,2,4,2]\)

. . \(\displaystyle \circ\, \circ\, \circ\, \circ\,||\, \circ\, \circ\,|\, \circ \, \circ\, \circ\:\text{ represents }[4,0,2,3]\)

. . \(\displaystyle |\,\circ\, \circ\, \circ\, \circ\, \circ\, \circ\,||\, \circ \, \circ\, \circ\:\text{ represents }[0.6.0.3]\)

. . \(\displaystyle \circ\, \circ\, \circ\, \circ\,|||\, \circ\, \circ\, \circ \, \circ\, \circ\:\text{ represents }[4,0,0,5]\)


\(\displaystyle \text{For each of the 3 dividers, there are 10 choices for locations.}\)

\(\displaystyle \text{Hence, there are: }\:10^3 = 1000\text{ ways when there are 8 in the first box.}\)


Get the idea?

 
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