Combinations...4

mathdad

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Apr 24, 2015
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Find the number of combinations of 4 different color pencils taken 2 at a time.

I was told by a friend to use the following formula:

nCr = n! /[r! (n - r)!], where n is 4 and r is 2.

Let me see if I can do this.

4C2 = 4!/[2!(4 - 2)!]

4C2 = 24/[2(2)!]

4C2 = 24/[2(2)]

4C2 = 24/4

4C2 = 6

There are 6 combinations.

You say?
 
Find the number of combinations of 4 different color pencils taken 2 at a time.

I was told by a friend to use the following formula:

nCr = n! /[r! (n - r)!], where n is 4 and r is 2.

Let me see if I can do this.

4C2 = 4!/[2!(4 - 2)!]

4C2 = 24/[2(2)!]

4C2 = 24/[2(2)]

4C2 = 24/4

4C2 = 6

There are 6 combinations.

You say?
Correct
 
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