mathdad
Full Member
- Joined
- Apr 24, 2015
- Messages
- 925
Find the number of combinations of four names, Matthew, Ben, Greg, John, taken three at a time.
Let me see. I don't want to write each name over and over again.
Let M = Matthew, B = Ben, G = Greg, and J = John.
Combinations
{M, B, G,}, {M, G, J}, {M, B, J}, {B, G, J}
The book tells me that each combination consisting of three objects determines 3! = 3x 2 x 1 = 6 permutations of the three objects in the combination.
Here is my guess for the first combination, which is {M, B, G}:
MBG, MGB, BMG, GMV, GBM, BGM
I would need to do this for every combination.
You say?
Let me see. I don't want to write each name over and over again.
Let M = Matthew, B = Ben, G = Greg, and J = John.
Combinations
{M, B, G,}, {M, G, J}, {M, B, J}, {B, G, J}
The book tells me that each combination consisting of three objects determines 3! = 3x 2 x 1 = 6 permutations of the three objects in the combination.
Here is my guess for the first combination, which is {M, B, G}:
MBG, MGB, BMG, GMV, GBM, BGM
I would need to do this for every combination.
You say?