College Algebra

[lakers]

Find the domain y= 3x/x+2

Find the center and radius of the circle whose equation is
x^(2)+y^(2)-4x+8y=26

 

[Deleted member 4993]

Find the domain y= 3x/x+2

Find the center and radius of the circle whose equation is
x^(2)+y^(2)-4x+8y=26

Please share with us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.

 

[JuicyBurger]

Find the domain y= 3x/x+2

Find the center and radius of the circle whose equation is
x^(2)+y^(2)-4x+8y=26

Hint!

What is domain? it is every value that X can be. So... what CAN'T X be? (What can you not divide by?)

For the center and radius of the circle you need to get it into the standard equation

\(\displaystyle (x-h)^2 + (y-k)^2 = r^2\)

Hope this helps some

 

[mmm4444bot]

I'll contribute a little free sauce, to the juicy burger below.

For the center and radius of the circle you need to get it into the standard equation by completing the square in x and y.

Oh, and we need to type parentheses around any numerator OR denominator that is an algebraic expression. Otherwise, the typing is not clear.

EG:

3x/x+2 means this: \(\displaystyle \frac{3x}{x} \ + \ 2\)

3x/(x + 2) means this: \(\displaystyle \frac{3x}{x + 2}\)

Do you understand the difference?