college algebra

[collegealgebrax3]

how do you solve this
6sqrtx=x

 

[Deleted member 4993]

how do you solve this
6sqrtx=x

Do you know - how to solve:

x[sup:8hncgxu9]2[/sup:8hncgxu9] = 36x

 

[collegealgebrax3]

6sqrt of x=x
did you square x and then square 6?

 

[Denis]

RULE: SQRT(n) squared = n

SQRT(4) squared = 2 squared = 4 : kapish?

 

[Mrspi]

how do you solve this
6sqrtx=x

I'd square both sides:

(6 sqrt(x) )[sup:3vgwyeo2]2[/sup:3vgwyeo2] = x[sup:3vgwyeo2]2[/sup:3vgwyeo2]

6[sup:3vgwyeo2]2[/sup:3vgwyeo2] * [sqrt(x)][sup:3vgwyeo2]2[/sup:3vgwyeo2] = x[sup:3vgwyeo2]2[/sup:3vgwyeo2]


36 x = x[sup:3vgwyeo2]2[/sup:3vgwyeo2]

Get 0 on one side..

0 = x[sup:3vgwyeo2]2[/sup:3vgwyeo2] - 36x

Now...factor the non-zero side. Once you have a product on the right side (in this problem), remember that if the product of two or more factors is 0, then at least one of the factors must be equal to 0.