How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2
K kycats2003 New member Joined Jul 1, 2005 Messages 2 Jul 1, 2005 #1 How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Jul 1, 2005 #2 kycats2003 said: How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2 Click to expand... Domain Issues are FIRST. x musn't be -4/3 or 1. Why is that? Multiply everything by the common denominator. (3x+4)(x-1) Giving 3(x-1) + 2(3x+4) = 2(3x+4)(x-1) Expand, Simplify, Solve, Check
kycats2003 said: How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2 Click to expand... Domain Issues are FIRST. x musn't be -4/3 or 1. Why is that? Multiply everything by the common denominator. (3x+4)(x-1) Giving 3(x-1) + 2(3x+4) = 2(3x+4)(x-1) Expand, Simplify, Solve, Check
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Jul 1, 2005 #3 kycats2003 said: How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2 Click to expand... Be CAREFUL when you type equations; that one needs brackets: 3 / (3x + 4) + 2 / (x - 1) = 2 The way you have it means: 3/3x + 4 + 2/x - 1 = 2 1/x + 2/x = 2 - 4 + 1 3/x = -1 x = -3
kycats2003 said: How do I solve for x in the problem: 3/3x+4 + 2/x-1 = 2 Click to expand... Be CAREFUL when you type equations; that one needs brackets: 3 / (3x + 4) + 2 / (x - 1) = 2 The way you have it means: 3/3x + 4 + 2/x - 1 = 2 1/x + 2/x = 2 - 4 + 1 3/x = -1 x = -3
