College Algebra LOGS

[killotin]

2^x+1 . 2^-2=1/8

This is part of the log functions chapter we are doing right now

WORK DONE :

I know that I have to get all the bases to be equal to 2 so I did

2^x+1 . 2^-2 = 1/2^3

Then I got stuck because of the fractions.

Help :?:

 

[soroban]

Hello, killotin!

You were off to a good start . . .

2^x+1·2^-2 .= .1/8
.

We have: . 2^x-1 .= .1/2³ .= .2^-3 . <--- There is the magic step!

Equate exponents: . x - 1 .= .-3 . ---> . x = -2

 

[stapel]

Multi-post.

And another.