College Algebra help PLEEEEEZE!

[jlhmom]

I am working on a task in college algebra.....

h = -16t² + 48t + 10
dh/dt = -32t + 48
dh/dt = 0 when 32t=48 that's when t=48/32 = 1.5.
So the maximum height occurs after 1.5 seconds.
h = -16(1.5)² + 48*1.5 + 10
h = -36 + 72 + 10
h = 46 feet

What I need to know is HOW did this person get the dh/dt that is listed above?

 

[mmm4444bot]

What I need to know is HOW did this person get the dh/dt that is listed above?

The expression dh/dt comes from calculus.

Are you taking a calculus course? You posted on the Intermediate/Advanced Algebra board.

If you have an exercise that asks you to find the maximum value of h, calculus is not required; there are algebraic methods to do that.

Cheers ~ Mark

 

[pka]

I am working on a task in college algebra.....
h = -16t² + 48t + 10
dh/dt = -32t + 48
dh/dt = 0 when 32t=48 that's when t=48/32 = 1.5.
So the maximum height occurs after 1.5 seconds.
h = -16(1.5)² + 48*1.5 + 10
h = -36 + 72 + 10
h = 46 feet

What I need to know is HOW did this person get the dh/dt that is listed above?

This method is definitely not college algebra.
That is derivative learned in a basic calculus course.

To do this question in college algebra, one would find the vertex of the parabola \(\displaystyle -16t^2+48t+10.\). That is the high point.