Question:
The circle, centre (p, q) has radius 25, meets the x axis at (-7, 0) and (7, 0), where q > 0. Find the value of p and q.
What I have tried so far:
Formed an equation -
\(\displaystyle (x - p)^2 + (y - q)^2 = 625\)
Tried to sub in x = 7 and y = 0,
\(\displaystyle (7 - p)^2 + q^2 = 625\)
\(\displaystyle 7 - p + q = 25\)
\(\displaystyle 7 - p = 25 - q\)
-p = 25 - q - 7
\(\displaystyle p = q - 25 + 7\)
\(\displaystyle p = q - 18\)
Can someone point me in the right direction to get the answer of p = 0, q = 24
Thanks
The circle, centre (p, q) has radius 25, meets the x axis at (-7, 0) and (7, 0), where q > 0. Find the value of p and q.
What I have tried so far:
Formed an equation -
\(\displaystyle (x - p)^2 + (y - q)^2 = 625\)
Tried to sub in x = 7 and y = 0,
\(\displaystyle (7 - p)^2 + q^2 = 625\)
\(\displaystyle 7 - p + q = 25\)
\(\displaystyle 7 - p = 25 - q\)
-p = 25 - q - 7
\(\displaystyle p = q - 25 + 7\)
\(\displaystyle p = q - 18\)
Can someone point me in the right direction to get the answer of p = 0, q = 24
Thanks