In a circle of diameter 20 the radius is 10.
We are considering an isosceles triangle with congruent sides of length 10 and an altitude from the vertex angle of length 6. Therefore, if y is half the length of the cord \(\displaystyle y^2 + 6^2 = 10^2 \quad \Rightarrow \quad y = 8.\)
So the length of the cord is 16.
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