Chemical Compounds

[Richay]

Two kgs of iron was melted with 7 kgs of other metals to make the alloy. If 1440 grams of the alloy was required then how many kilograms of iron should be used?

What is the equation or steps for solving this problem?

 

[soroban]

Hello, Richay!

Two kgs of iron was melted with 7 kgs of other metals to make the alloy.
If 1440 grams of the alloy was required, then how many kilograms of iron should be used?

Very funny (not!) . . . they have kilograms and grams.
Change the amount of alloy to \(\displaystyle 1.44\text{ kg}\)

The alloy consists of two parts Iron to seven parts of Other metals.
The ratio of Iron to Other is \(\displaystyle \,2\,:\,7\)
Hence, the ratio of Iron to Alloy is \(\displaystyle \,2\,:\,9\)

We have: \(\displaystyle \L\,\frac{x}{1.44}\:=\:\frac{2}{9}\)

 

[Richay]

Hey, wait i'm confused again. Why did you change 1440 g to 1.44 kg. How does this occur? Help please

 

[stapel]

Why did you change 1440 g to 1.44 kg.

So all the units would be the same.

How does this occur?

Are you not familiar with metric units...?

Eliz.

 

[Richay]

Why did you change 1440 g to 1.44 kg.

So all the units would be the same.

How does this occur?

Are you not familiar with metric units...?

Eliz.

I am.

Let's see.
1,120 is the amount of other metals so. 1440 - 1120 = 320
My answer is 320 for iron used. :wink: