Cheesy Bill Cosby Math Joke

J

Jason76

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sin⁡btan⁡b=\displaystyle \dfrac{\sin b}{\tan b} = Cosby

Proof

sin⁡btan⁡b→sin⁡bsin⁡bcos⁡b\displaystyle \dfrac{\sin b}{\tan b} \rightarrow \dfrac{\sin b}{\dfrac{\sin b}{\cos b}}

sin⁡b(cos⁡bsin⁡b)=cos⁡b\displaystyle \sin b (\dfrac{\cos b}{\sin b}) = \cos b Cosby :rolleyes:
 
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