checking my work

J

jmsic

New member
Joined
Aug 31, 2009
Messages
11
Dx[(3x[sup:2ubvnfo1]3[/sup:2ubvnfo1]+4x[sup:2ubvnfo1]2[/sup:2ubvnfo1]-3)/x[sup:2ubvnfo1]2[/sup:2ubvnfo1]]
x[sup:2ubvnfo1]2[/sup:2ubvnfo1](9x[sup:2ubvnfo1]2[/sup:2ubvnfo1]+8x)-2x(3x[sup:2ubvnfo1]3[/sup:2ubvnfo1]+4x[sup:2ubvnfo1]2[/sup:2ubvnfo1]-3) ALL OVER (x[sup:2ubvnfo1]2[/sup:2ubvnfo1])[sup:2ubvnfo1]2[/sup:2ubvnfo1]
9x[sup:2ubvnfo1]4[/sup:2ubvnfo1]+8x[sup:2ubvnfo1]3[/sup:2ubvnfo1]-6x[sup:2ubvnfo1]4[/sup:2ubvnfo1]-8x[sup:2ubvnfo1]3[/sup:2ubvnfo1]+6x ALL OVER x[sup:2ubvnfo1]4[/sup:2ubvnfo1]
3x[sup:2ubvnfo1]4[/sup:2ubvnfo1]+6x ALL OVER x[sup:2ubvnfo1]4[/sup:2ubvnfo1]
3+6x[sup:2ubvnfo1]-3[/sup:2ubvnfo1]
(my teacher said no negative exponents)
3+(6/x[sup:2ubvnfo1]3[/sup:2ubvnfo1])

right?
 
You must log in or register to reply here.
Top