comeoneileen0405
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- Nov 21, 2005
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(2x)^4(4x)^6(8x)^2 = b
a. 2^28x^12
b. 2^26x^12
c. 2^22x^12
d. 2^20x^12
e. none of these
a. 2^28x^12
b. 2^26x^12
c. 2^22x^12
d. 2^20x^12
e. none of these
checking an answer
- Thread starter comeoneileen0405
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ryansmith069
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- Nov 9, 2005
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she wrote = B idiot!
Hello, comeoneileen0405!
2^4\cdot x^4)\cdot(4^6\cdot x^6)\cdot(8^2\cdot x^2) \;= \;2^4\cdot4^6\cdot8^2\cdot x^{12}\)
The coefficient is: \(\displaystyle \,(2^4)(2^2)^6(2^3)^2\;= \;2^4\cdot2^{12}\cdot2^6 \;=\;2^{22}\)
The answer is: \(\displaystyle \,(c)\;2^{22}x^{12}\)
We have: \(\displaystyle \
2^4\cdot x^4)\cdot(4^6\cdot x^6)\cdot(8^2\cdot x^2) \;= \;2^4\cdot4^6\cdot8^2\cdot x^{12}\)The coefficient is: \(\displaystyle \,(2^4)(2^2)^6(2^3)^2\;= \;2^4\cdot2^{12}\cdot2^6 \;=\;2^{22}\)
The answer is: \(\displaystyle \,(c)\;2^{22}x^{12}\)
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Thank you for sharing.ryansmith069 said:
Eliz.
P.S. to original poster: If you meant that you feel that "b" is the correct answer choice, rather than, as posted, that you are simplifying an expression for which "b" is the name, then please reply with that clarification. Thank you.