chain rule with logs

[Dorian Gray]

Greetings Mathematicians,

I was wondering if somebody could please look at my work for this problem: Differentiate the function y= [lnu]/[ln2u+1]


My answer is slightly different from the key that I have.

the key's answer is [1+ln2]/[u((1+ln2u)^2)]


Any comments, help, suggestions, and tips are always appreciated

 

[Deleted member 4993]

Greetings Mathematicians,

I was wondering if somebody could please look at my work for this problem: Differentiate the function y= [lnu]/[ln2u+1]


My answer is slightly different from the key that I have.

the key's answer is [1+ln2]/[u((1+ln2u)^2)]


Any comments, help, suggestions, and tips are always appreciated
View attachment 1710

Your answer and the key's answer are equivalent.

ln(2*U) = ln(2) + ln(U)

 

[Dorian Gray]

thank you

Thank you very much Subhotosh Khan for checking that over. I am extremely glad that they are the same. I kept redoing that problem and getting my answer but thought I was wrong (face palm).