Chain Rule Solution Help
- Thread starter Aboostani
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Steven G
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- Dec 30, 2014
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Maybe this is what you are asking about: How to go from [imath]4\sqrt{x}\cdot\sqrt{2 + \sqrt{x}}\;[/imath] to [imath]\;4\sqrt{x(2+\sqrt{x})}[/imath].
This is a property of square roots: [imath]\sqrt{X} \cdot \sqrt{Y} = \sqrt{X \cdot Y}[/imath] as long as X and Y are both positive.
This is a property of square roots: [imath]\sqrt{X} \cdot \sqrt{Y} = \sqrt{X \cdot Y}[/imath] as long as X and Y are both positive.