centripetal acceleration: If the TGV goes around a curve at

[soccerball3211]

The fast French train known as the TGV (Train Grande Vitesse) has a scheduled average speed of 216 km/h. (a) If the train goes around a curve at that speed and the magnitude of the acceleration experienced by the passengers is to be limited to 0.050g, what is the smallest radius of curvature for the track that can be tolerated? (b) At what speed must the train go around a curve with a 1.20 km radius to be at the acceleration limit?

For part A.) I got 72 km by using the equation a sub c = (v^2)/r, I then solved for r to obtain my result

For part B.) I got 27.8 km/hr by also using the equation a sub c = v^2/r, I then solved for v to obtain my result.

Are my answers correct?

 

[Gene]

I'm not sure what you did with the units, but...
g = 9.81 m/s/s
.05g=.4905 m/s/s

216 km/h = 216000/3600 = 60 m/s

Now the units are the same and you can use your equation to solve for r. Looks like a galloping decimal point?