center-radius form of eq. of circle

jsantos

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Feb 28, 2006
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find center-radius form of equation of circle with center (-2,-3) and tangent to the x-axis

(x+2)^2+(y+3)^2=r^2

i do not know how to find r^2

i was provided the answer (x+2)^2 + (y+3)^2=9

how do i come up with nine from r
 
How far is the center, (−2, −3), from the x-axis?
That is your radius.
 
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