mathstresser
Junior Member
- Joined
- Jan 28, 2006
- Messages
- 134
The mass mi is located on the point Pi. Find the moments Mx and My and the center of mass of the system.
m1=6, m2= 5, m3=10;
P1(1,5), P2(3,-2), P3(-2,-1)
I found that Mx= (6)(1)+(5)(3)+(10)(-2)=1 and My= (6)(5)+(5)(-2)+(10)(-1)=10
M=6+5+10=21
so the points are
x= 1/21 and y= 10/21 which is
(1/21,10/21)
But, the answer is
10; 1; (1/21,10/21)
How do they get the first two answers?
m1=6, m2= 5, m3=10;
P1(1,5), P2(3,-2), P3(-2,-1)
I found that Mx= (6)(1)+(5)(3)+(10)(-2)=1 and My= (6)(5)+(5)(-2)+(10)(-1)=10
M=6+5+10=21
so the points are
x= 1/21 and y= 10/21 which is
(1/21,10/21)
But, the answer is
10; 1; (1/21,10/21)
How do they get the first two answers?