Car reaction time

[Dorian Gray]

Greetings Mathematicians,

I was wondering if someone could please help me with the problem attached. I have no idea where to start. I attached a few equations that I need to use for the problem, but am having difficulties deciding which values correspond to which variables.

Any and all help, tips, ideas, suggestions are appreciated. Please help me get started in the right direction. Thank you.

 

[Dorian Gray]

drawing

Here is a drawing of my work so far. This is all I am able to come up with (and I am not sure if it is even remotely close).

Any and all help, comments, suggestions, ideas are much appreciated!

 

[Yogi]

They give 2 different scenarios so rather than lump it all together in 1 picture I would draw 2 separate pictures.

Reaction time is constant so the distance you travel in both scenarios before hitting the brakes can be x.

|-x-|--(56.7-x)------------|


|-x-|--(24.4-x)----|

You know initial velocity in both cases and ending velocity is 0, can you finish?

 

[Dorian Gray]

They give 2 different scenarios so rather than lump it all together in 1 picture I would draw 2 separate pictures.

Reaction time is constant so the distance you travel in both scenarios before hitting the brakes can be x.

|-x-|--(56.7-x)------------|


|-x-|--(24.4-x)----|

You know initial velocity in both cases and ending velocity is 0, can you finish?

Thank you very much Yogi for the suggestion and drawing. It is much appreciated.
I think I can handle it from here now. Thanks again!

 

[Deleted member 4993]

Greetings Mathematicians,

I was wondering if someone could please help me with the problem attached. I have no idea where to start. I attached a few equations that I need to use for the problem, but am having difficulties deciding which values correspond to which variables.

Any and all help, tips, ideas, suggestions are appreciated. Please help me get started in the right direction. Thank you.

View attachment 2188View attachment 2189

Let the reaction time in both the cases be 't' sec

Then

distance traveled at 80.5 km/h (22.36111 m/s) is 22.3611*t m

distance traveled at 48.3 km/h (13.41667 m/s) is 13.41667*t m

So

at 80.5 km/h the distance traveled under constant deceleration is (56.7 - 22.3611*t) m

and

at 48.3 km/h the distance traveled under constant deceleration is (24.4 - 13.41667*t) m

Now continue....

 

[Dorian Gray]

Let the reaction time in both the cases be 't' sec

Then

distance traveled at 80.5 km/h (22.36111 m/s) is 22.3611*t m

distance traveled at 48.3 km/h (13.41667 m/s) is 13.41667*t m

So

at 80.5 km/h the distance traveled under constant deceleration is (56.7 - 22.3611*t) m

and

at 48.3 km/h the distance traveled under constant deceleration is (24.4 - 13.41667*t) m

Now continue....

Greetings Subhotosh Khan,

Thank you very much for your help as well. I apologize for not responding sooner. I was able to solve the problem with your way and Yogi's way. This is my first physics class so I appreciate both of your help.