capillary

logistic_guy

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Apr 17, 2024
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here is the question

A 0.4\displaystyle 0.4-mm-diameter glass tube is inserted into water at 20°C\displaystyle 20°C in a cup. The surface tension of water at 20°C\displaystyle 20°C is σs=0.073\displaystyle \sigma_s = 0.073 N/m. The contact angle can be taken as zero degrees. The capillary rise of water in the tube is

(a) 2.9\displaystyle 2.9 cm
(b) 7.4\displaystyle 7.4 cm
(c) 5.1\displaystyle 5.1 cm
(d ) 9.3\displaystyle 9.3 cm
(e) 14.0\displaystyle 14.0 cm


my attemb
the notation of the question is a little ambiguous
do it mean σs=Σs\displaystyle \sigma_s = \Sigma_s
i don't know σs\displaystyle \sigma_s☹️
i know Σs\displaystyle \Sigma_s
 
here is the question

A 0.4\displaystyle 0.4-mm-diameter glass tube is inserted into water at 20°C\displaystyle 20°C in a cup. The surface tension of water at 20°C\displaystyle 20°C is σs=0.073\displaystyle \sigma_s = 0.073 N/m. The contact angle can be taken as zero degrees. The capillary rise of water in the tube is

(a) 2.9\displaystyle 2.9 cm
(b) 7.4\displaystyle 7.4 cm
(c) 5.1\displaystyle 5.1 cm
(d ) 9.3\displaystyle 9.3 cm
(e) 14.0\displaystyle 14.0 cm


my attemb
the notation of the question is a little ambiguous
do it mean σs=Σs\displaystyle \sigma_s = \Sigma_s
i don't know σs\displaystyle \sigma_s☹️
i know Σs\displaystyle \Sigma_s
Given:
The surface tension of water at 20°C\displaystyle 20°C is σs=0.073\displaystyle \sigma_s = 0.073 N/m
Read textbook and consult Google - thou shall know,,,,,,,,
 
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