Cant make the equation to get t (price of train ticket, in terms of "t")

[Underside]

I solved the problem by plugging in values. But i want to know how to form a equation to solve this

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The price of a train ticket purchased in the train station or from a conductor is 15% less during off-peak hours than it is during peak hours. If a ticket is purchased from the conductor, an 11% surcharge is added to the price.

Alec purchased a ticket from the conductor during off-peak hours and paid a total of t dollars. Which of the following, in terms of t, represents the price he would have paid if he had purchased the ticket in the train station during peak hours?

. . . . .\(\displaystyle \mbox{A) }\, \dfrac{t}{0.96}\)

. . . . .\(\displaystyle \mbox{B) }\, 0.96\,t\)

. . . . .\(\displaystyle \mbox{C) }\, \dfrac{t}{(0.85)\,(1.11)}\)

. . . . .\(\displaystyle \mbox{D) }\, (0.85)\,(1.11)\,t\)

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[JeffM]

Please resend the problem so it can be read without breaking my neck. And just how did you plug in values? If you show us that, you must have been close to setting up an equation on your own.

 

[Dr.Peterson]

I solved the problem by plugging in values. But i want to know how to form a equation to solve this.

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I've modified the picture so I can see it better:


What I would do to solve this is to do what you probably did to check each answer, but using a new variable. Suppose that the price in the station during peak hours is p. Apply the appropriate percentages to that, to arrive at an expression for t. Then solve for t.

Show us whatever you are able to do, and we can give you additional suggestions. Without seeing your work, we can't tell what help would be useful to you.

 

[Underside]

The other thread you posted (Feb.11) was answered:
you did not respond.
Same story with this thread?

Oh sorry about that I couldn't solve it and moved on so I forgot about the post.

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[Underside]

I've modified the picture so I can see it better:
View attachment 9349

What I would do to solve this is to do what you probably did to check each answer, but using a new variable. Suppose that the price in the station during peak hours is p. Apply the appropriate percentages to that, to arrive at an expression for t. Then solve for t.

Show us whatever you are able to do, and we can give you additional suggestions. Without seeing your work, we can't tell what help would be useful to you.

I did it by two methods as shown in pic below, i would like to know if there is anymore alternative method. Thanks

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[Underside]

Please resend the problem so it can be read without breaking my neck. And just how did you plug in values? If you show us that, you must have been close to setting up an equation on your own.

I uploaded the photo with my solution. I did got a equation. And now want to know if there is any alternative method rather than these two.

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[stapel]

I did it by two methods as shown in pic below, i would like to know if there is anymore alternative method. Thanks

It looks to my like the exercise is ambiguous. Is the surcharge on the purchase price (after the 15% during off-peak hours), or only always on the full price?

The answer will depend upon how that surcharge is defined.

 

[Dr.Peterson]

I did it by two methods as shown in pic below, i would like to know if there is anymore alternative method. Thanks

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I did it more or less like your left-hand method, but not carrying out the multiplications (because the choices suggest leaving it as a product, and because that is often more efficient).

If the price during peak hours is p, then off-peak it is (1 - 0.15)p = 0.85p; and from the conductor it is (1 + 0.11) times that: (1.11)(0.85)p = t. Solving for p, p = t/[(1.11)(0.85)].

I think that's the best way to do it.