Can you please help w/ [(5/3c) + (7/2v)] / [(c/6) - (3/cv)]

gnarlycarly227

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Jun 1, 2008
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[(5/3c) + (7/2v)] / [(c/6) - (3/cv)]

Please show me how to do it step by step.

Thank you sooo much! :)
 
[(5/3c) + (7/2v)] / [(c/6) - (3/cv)] means \(\displaystyle \frac{\frac{5}{3}c+ \frac{7}{2}v}{\frac{c}{6}-\frac{3}{c}v}\)

Is this the problem? And what is your question? Just to start I would multiply both numerator and denominator by th least common denominator, 6c, and see what it looks like then.
 
gnarlycarly227 said:
[(5/3c) + (7/2v)] / [(c/6) - (3/cv)]

Please show me how to do it step by step.
Until you post the instructions (that is, an actual question), I'm afraid there is nothing to "do". Also, as mentioned above, your formatting makes your meaning quite unclear. It would help to use the formatting explained in the articles in the links you saw in the "Read Before Posting" thread. :oops:

Also, if you are needing all of the steps done for you, this would indicate that you actually need lessons. (If you understood the material, naturally you'd be able to get started, and/or would be asking for a boost, rather than hoping for complete worked solutions.) :shock:

So, when you reply with the instructions, please either include all of your work and reasoning so far, or else specify the topics over which you are needing lesson links. :idea:

Please be complete. Thank you! :D

Eliz.
 
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