can you help with asymptotes

mathhelp1a

New member
Joined
Oct 4, 2009
Messages
40
( x - 5 ) / ( x ^2 - 25 )

The vertical asymptote is only -5 ??
cause x-5 cancels out???
the horizontal asymptote is only y=0 ??

there is no slant asymptote??
 
[x-5]/[x^2-25]= 1/[x+5]

vertical assymptote at x=-5
at x=-00 y=-0, as x increases y decreases and goes to -00 at x=-5

at x=-5+, y=00, as x increases y decreases and goes to +0 as x approachs 00

vertical asstymptotes at x=-5
horizontal assymptotes at y=0
no slant assymptotes

I believe this is right
Arthur
 
Top