Can you figure this out?

[dennisinoc]

I cannot figure this one out...

Need to proportionally add a number to a series of numbers based on the size of the number.

Example; the number to 50 is to be added to this series of numbers proportionally based on their size

500
100
200
300


??? anyone?

 

[Deleted member 4993]

I cannot figure this one out...

Need to proportionally add a number to a series of numbers based on the size of the number.

Example; the number to 50 is to be added to this series of numbers proportionally based on their size

500
100
200
300


??? anyone?

Suppose you needed to add 'a' to following set of numbers (proportionately)

3*x
5*x
7*x
9*x

then I would add

3*x + 3*a
5*x + 5*a
7*x + 7*a
9*x + 9*a

or we can do:

3x + a
5x + (5/3)*a
7x + (7/3)*a
9x + 3*a

 

[dennisinoc]

Thanks for the reply,

50 or "a", would be better explained, it would be divided and proportionally distributed over the numbers given.


I still do not have the answer.

 

[Deleted member 4993]

I still do not have the answer.

If the example problem does not guide you to the answer - I am misinterpreting the problem.

Where are you stuck exactly?

 

[dennisinoc]

I wasn't able, or maybe I didn't understand your solution.

Again, I am trying to add an amount to a series of numbers,

say we are adding 50 to;

67
56
79
12
9

I can divide the count of numbers (5) into 50 = 10, then add 10 to each number, this does not evenly or proportionally divide 50 among the numbers.

Sorry for my poor explanation.

 

[Deleted member 4993]

Now I understand your question a little better

I cannot figure this one out...

Need to proportionally add a number to a series of numbers based on the size of the number.

Example; the number to 50 is to be added to this series of numbers proportionally based on their size

500
100
200
300


??? anyone?

Suppose you needed to add 'a' to following set of numbers (proportionately)


t
u
v
w
x
y
z

find Sum of above S = (t+u+v+w+x+y+z)

Then You would add

t + t*a/S
u + u*a/S
v + v*a/S
.
.
and so on

 

[dennisinoc]

Works perfectly!!!!



Thanks!!