given cosW=24/25 and 0<W<pi/2 find sinW? my answer cosW=x/r cosW=x/25 cos25=W is W=.9064?
J jas397 New member Joined Jan 1, 2006 Messages 13 Jan 2, 2006 #1 given cosW=24/25 and 0<W<pi/2 find sinW? my answer cosW=x/r cosW=x/25 cos25=W is W=.9064?
pka Elite Member Joined Jan 29, 2005 Messages 11,995 Jan 2, 2006 #2 If 0<W<π2\displaystyle 0 < W < \frac{\pi }{2}0<W<2π then sin(W)=1−cos2(W)\displaystyle \sin (W) = \sqrt {1 - \cos ^2 (W)}sin(W)=1−cos2(W).
If 0<W<π2\displaystyle 0 < W < \frac{\pi }{2}0<W<2π then sin(W)=1−cos2(W)\displaystyle \sin (W) = \sqrt {1 - \cos ^2 (W)}sin(W)=1−cos2(W).
