Can someone show me the first step?

mathimpaired

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Feb 11, 2006
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The sum of two integers is 158. Find the two integers if the larger is 10 less than twice the smaller.


I know this is probably super easy, but I'm lost. I think I can probably figure it out if someone points me in the right direction. Thanks.
 
mathimpaired said:
The sum of two integers is 158. Find the two integers if the larger is 10 less than twice the smaller.
x = smaller integer; then larger integer = 2x - 10; carry on
 
I still don't get it. I'm feeling very stupid right now. I've read my book, looked over my notes, read the reply, and I still don't get it. The problem looks like it should be easy to solve, but I'm still very lost. :cry:
 
\(\displaystyle \L
\begin{array}{r}
m + n & = & 158 \\
m + 10 & = & 2n \\
\left( {2n - 10} \right) + n & = & 158 \\
\end{array}\)
 
Eureka!!!! It only took me a couple of hours, but I finally figured it out!
The answer is 102. :D Thanks for all your help. I love this board.

Geez, why is it I can write a three page essay for English in a half hour and get an A, but it takes me forever to solve a simple math problem?
 
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