(3x-2)+(2x=4)+(3x-3)=89
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Feb 11, 2009 #2 Re: can someone show me how to do this? >(3x-2)+(2x=4)+(3x-3)=89 You don't say what you are trying to do. As written, is there a typo? If so, make the correction and also include the instructions.
Re: can someone show me how to do this? >(3x-2)+(2x=4)+(3x-3)=89 You don't say what you are trying to do. As written, is there a typo? If so, make the correction and also include the instructions.
F fasteddie65 Full Member Joined Nov 1, 2008 Messages 360 Feb 13, 2009 #3 Re: can someone show me how to do this? darlenegriffith said: (3x-2)+(2x=4)+(3x-3)=89 Click to expand... I'm thinking that, instead of (3x-2)+(2x=4)+(3x-3)=89, it should be (3x-2)+(2x+4)+(3x-3)=89. The reason for my conclusion is that the + and = symbols are on the same key. Anyway, combine like terms: 8x -1 = 89. This should be easy to solve.
Re: can someone show me how to do this? darlenegriffith said: (3x-2)+(2x=4)+(3x-3)=89 Click to expand... I'm thinking that, instead of (3x-2)+(2x=4)+(3x-3)=89, it should be (3x-2)+(2x+4)+(3x-3)=89. The reason for my conclusion is that the + and = symbols are on the same key. Anyway, combine like terms: 8x -1 = 89. This should be easy to solve.
