Hello, moronatmath!
An open box is to be made from a flat square piece of material 8 inches in length and width
by cutting equal squares of length x from the corners and folding up the sides.
Write the volume V of the box as a function of x.
Leave it as a product of factors; you do not have to multiply out the factors.
If we write the domain of the box as an open interval in the form (a,b),
then what is a? \(\displaystyle \;\) and what is b?
From an 8-by-8 inch square, four congruent corners squares are removed.
Code:
: x : 8-2x : x :
*---+-------+---*
|:::: ::::| x
+ - * - - - * - +
| : : |
| : : | 8-2x
| : : |
+ - * - - - * - +
|:::: ::::| x
*---+-------+---*
* x : 8-2x : x *
The sides are folded up and an open-top box is formed:
Code:
*-------------*
/ | / | x
/ *---------/ *
/ / / /
*-------------* / 8-2x
x | | /
*-------------*
8-2x
The volume of a box is, of course: \(\displaystyle \:V\;=\;L\,\times\,W\,\times\,H\)
So we have: \(\displaystyle \:V\;=\;(8\,-\,2x)(8\,-\,2x)x \:=\:x(8\,-\,2x)^2\)
The domain of \(\displaystyle x\) is: \(\displaystyle (0,\,4)\)
If \(\displaystyle x\) (side of the removed square) is 0, no squares are removed.
\(\displaystyle \;\;\)There are no "sides" to fold up.
\(\displaystyle \;\;\)The volume of the so-called box would be 0.
If \(\displaystyle x\,=\,4\), we have removed
all of the original square.
\(\displaystyle \;\;\)There is no material to form the box, so its volume is 0.
Hence, the value of \(\displaystyle x\) must lie
between 0 and 4.