Can someone explain why the 1 disappears?

[I_am_not_a_robot_I_promis]

Simplifies to(according to others):

I don't understand why the 1 disappears. Can someone explain?
Or did I do something wrong? The original equation was:

 

[tkhunny]

'1' cannot disappear. That doesn't happen.

[math]\dfrac{y+x}{y}\cdot v[/math]
[math]\left(\dfrac{y}{y}+\dfrac{x}{y}\right)\cdot v[/math]
[math]\left(1+\dfrac{x}{y}\right)\cdot v[/math]
[math]1\cdot v+\dfrac{x}{y}\cdot v[/math]
[math]v+\dfrac{x\cdot v}{y}[/math]
There's a whole lot of NOPE going on in the dispute you have brought to us.

Use appropriate properties and groupings.

[math](y+x)\cdot \dfrac{v}{y}[/math]
Lots of ways to create equivalent expressions.

 

[Steven G]

[math]\dfrac{x}{y}*v[/math] is some value. Now adding this value to 1 will never give you back that value. Now adding something to zero or multiply something by 1 will give you back the same value

 

[Dr.Peterson]

View attachment 21180
Simplifies to(according to others):
View attachment 21181
I don't understand why the 1 disappears. Can someone explain?
Or did I do something wrong? The original equation was:
View attachment 21182

Perhaps this shows that you know more than you realize -- enough to determine that someone else is wrong!

When something doesn't make sense, you don't need to assume it's your fault. Instead, realize that something and something+1 can never be equal, so clearly these "others" can't be trusted.

Of course, if you haven't quoted everything fully, it's possible that you misunderstood what they were claiming, and they meant something that was correct. (By the way, this is an expression, not an equation.)