Can someone check this equation for me?

[JWS]

My equation is: h(x) = 2x^2 -7x +5 h(-1/5)

I have worked it out to what I believe the answer is: h(-1/5) = 210/25

I will be happy to show my work but did not want to clutter space if my answer is correct

Thanks...

 

[Someone2841]

My equation is: h(x) = 2x^2 -7x +5 h(-1/5)

I have worked it out to what I believe the answer is: h(-1/5) = 210/25

I will be happy to show my work but did not want to clutter space if my answer is correct

Thanks...

\(\displaystyle h(\frac{-1}{5}) = 2(\frac{-1}{5})^{2} -7(\frac{-1}{5}) +5 = \frac{2}{25} + \frac{7}{5} + 5 = \frac{2}{25} + \frac{35}{25} + \frac{125}{25} = \frac{162}{25}\)