can some one help please?

[mathhelp1a]

differentiate and simplify as indicated

y= 3/ sqrt x^2

is it -3x / x^2

is that right

 

[BigGlenntheHeavy]

\(\displaystyle y \ = \ f(x) \ = \ \frac{3}{\sqrt (x^{2})} \ = \ \frac{3}{|x|}\)

\(\displaystyle Hence, \ f'(x) \ = \ \frac{-3}{x|x|}\)

 

[mathhelp1a]

so the answer is -3 / absoulute x^2
how did sqrt x get changed to abosoulte x ???

 

[BigGlenntheHeavy]

\(\displaystyle Hey, \ y= 3/ sqrt \ x^2 \ is \ y \ = \ \frac{3}{\sqrt(x^{2})} \ is \ \frac{3}{|x|}.\)