Can not figure this out!!

H

happysmiler07

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Apr 5, 2014
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Ive been working on this for two weeks and Im always slightly off.

Draw a graph that contains two x-intercepts; at one, the graph crosses the x-axis, and at the other the graph touches the x axis.
 
happysmiler07 said:
Ive been working on this for two weeks and Im always slightly off.

Draw a graph that contains two x-intercepts; at one, the graph crosses the x-axis, and at the other the graph touches the x axis.
Click to expand...
Please explain what you mean by "always slightly off". What have you tried? At what answers have you arrived? How are you "off"?

Thank you! ;)
 
stapel said:
Please explain what you mean by "always slightly off". What have you tried? At what answers have you arrived? How are you "off"?

Thank you! ;)
Click to expand...

Well please note our instructor has allowed us to use wolframalpha.com for graphing. I have tried several different equations but the closest are:
y=(x-2)(x-3)(x+2)^2(x+3) but thats too many thats 4x intercepts.

Then I have -2x+1y=2 but then thats only 1 x intercept.

Also y=x^22-5x+6 which gives me 2x intercepts but not for what is required.

I cant figure out how to set up the equation that contains two x-intercepts; at one, the graph crosses the x-axis, and at the other the graph touches the x axis
 
happysmiler07 said:
Well please note our instructor has allowed us to use wolframalpha.com for graphing. I have tried several different equations but the closest are:
y=(x-2)(x-3)(x+2)^2(x+3) but thats too many thats 4x intercepts.

Then I have -2x+1y=2 but then thats only 1 x intercept.

Also y=x^22-5x+6 which gives me 2x intercepts but not for what is required.

I cant figure out how to set up the equation that contains two x-intercepts; at one, the graph crosses the x-axis, and at the other the graph touches the x axis
Click to expand...
This illustrates one of the problems which occurs when a student "uses technology" to get instant magical answers, rather than doing the work himself: he has little to no understanding of what is going on behind the scenes, as it were.

To learn what is being asked of you, please try this article. ;)
 
Hello, happysmiler07!

Two weeks? . . . and still no clue?

Draw a graph that has two x-intercepts.
At one, the graph crosses the x-axis.
At the other, the graph is tangent to the x axis.
Click to expand...

If the graph has \(\displaystyle x\)-intercept, \(\displaystyle a\),
. . then the function has the factor \(\displaystyle (x-a)^n.\)

If \(\displaystyle n\) is odd, the graph crosses the \(\displaystyle x\)-axis at \(\displaystyle x = a.\)

If \(\displaystyle n\) is even, the graph is tangent to the \(\displaystyle x\)-axis at \(\displaystyle x = a.\)


One solution is: .\(\displaystyle y \;=\;(x+2)(x-3)^2\)

The graph crosses the \(\displaystyle x\)-axis at \(\displaystyle x = -2\)
. . and is tangent to the \(\displaystyle x\)-axis at \(\displaystyle x = 3.\)

Code: 
            |
            |              * 
            | 
            | *           *
           *|   *        *
         *  |    *     *
    - - * - + - - - * - - - - -
       -2   |       3
       *    |
            |
            |
      *     |
            |

 
stapel said:
You can just copy the answer above. But in case you need to know this stuff (like for the next test), you might want to think about learning the concepts anyway. ;)
Click to expand...

Figured it out!!

y = (x-1)(x+1)^2(x+1)
x intercepts are -1,1 y intercept - 1

gra.JPG


and just took a test got a 73% not exceptional, but passing. And no, I will NEVER need this in life. Thanks for the help, I'm sure I'll be back for another query.
 
happysmiler07 said:
Figured it out!!

gra.JPG


Click to expand...

Hi happysmiler07:

The image link above fails because you linked to a site that first requires logging in.

Next time, consider uploading images to the forum server and posting as attachments (See the FAQ).

Cheers :cool:
 
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