integral of 2/(x^2+4x+5) dx Please help! Thanks!
C cheffy Junior Member Joined Jan 10, 2007 Messages 73 Jan 10, 2007 #1 integral of 2/(x^2+4x+5) dx Please help! Thanks!
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Jan 11, 2007 #2 Re: u substitution(?) cheffy said: integral of 2/(x^2+4x+5) dx Click to expand... Completing the square in the denominator would be a good start. Can you see what this might lead to?
Re: u substitution(?) cheffy said: integral of 2/(x^2+4x+5) dx Click to expand... Completing the square in the denominator would be a good start. Can you see what this might lead to?
M mark New member Joined Feb 28, 2006 Messages 43 Jan 11, 2007 #3 u substition is not going to work you either have to use trig subsitition or partial fractions just complete the square in the demonator x^2 + 4x + 5 = x^2 +4x + 4 +5 -4 = (x+2)^2 +1 which equals intergral 2/((x+2)^2+1) which then can be solved using trig subsition
u substition is not going to work you either have to use trig subsitition or partial fractions just complete the square in the demonator x^2 + 4x + 5 = x^2 +4x + 4 +5 -4 = (x+2)^2 +1 which equals intergral 2/((x+2)^2+1) which then can be solved using trig subsition
C cheffy Junior Member Joined Jan 10, 2007 Messages 73 Jan 11, 2007 #4 I did what you said and I see how I should get my answer, but how do I get rid of the 5 in the denominator?
I did what you said and I see how I should get my answer, but how do I get rid of the 5 in the denominator?
M mark New member Joined Feb 28, 2006 Messages 43 Jan 11, 2007 #5 that was a typo is was supposed to be 1