can anyone tell me where I did wrong?9x−2(x+0.5)=2(x+3.5)−3(2x−1)9^x-2^(x+0.5)=2^(x+3.5)-3^(2x-1)

[ALIAHMAD]

taking $$2^x$$=a and $$3^x$$=b

now the equation becomes $$b^2-a√2 =8a√2-b^2/3$$

 

[ALIAHMAD]

sorry just realised while writing question what I did wrong
can anyone tell me how to delete this thread?

 

[Steven G]

You can't delete the thread.

 

[BigBeachBanana]

sorry just realised while writing question what I did wrong
can anyone tell me how to delete this thread?

You can share your solution. Someone might benefit from it.

 

[lookagain]

now the equation becomes $$b^2-a√2 =8a√2-b^2/3$$

If you post more threads, please do not put your equation in the title. Your equation,
In non-Latex, was really this:

9^x - 2^(x + 0.5) = 2^(x + 3.5) - 3^(2x - 1)

Then, after your substitutions, it would become the equation you wrote in post # 1.