What is the question? What did you want to find?[imath]\sqrt{ \log_{ 0.4 }({ x- { x }^{ 2 } }) \phantom{\tiny{!}}}[/imath]
SIR PLEASE FIND THE DOMAIN OF THE ABOVE FUNCTION OR IN SIMPLE WORDS WHAT ARE THE VALUES OF XWhat is the question? What did you want to find?
Please post the complete problem - along with your attempt to solve it.
I DIDN'T QUITE UNDERSTAND IT.The honest answer to your question is no, nobody can solve this.
Please read the forum's guidelines. Here's a link to a summary.I REALLY NEED THE ANSWER
YES, I CAN SOVE IT THE DOMAIN OF THE FUNCTION [math]\sqrt{ x- { x }^{ 2 } \phantom{\tiny{!}}}[/math] IS x belongs to [0,1]Please read the forum's guidelines. Here's a link to a summary.
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Do you have any experience finding domains? For example, are you able to find the domain of this simpler version?
\(\displaystyle \sqrt{x - x^2}\)
[imath]\;[/imath]
YEAH LIKE IF THE BASE OF LOG IS 0<x<1 THEN WHILE REMOVING LOG THE SIGN OF INEQUALITY CHANGESPlease read the forum's guidelines. Here's a link to a summary.
Posting Guidelines (Summary)
Welcome to our tutoring boards! :) This page summarizes main points from our posting guidelines. As our name implies, we provide math help (primarily to students with homework). We do not generally post immediate answers or step-by-step solutions. We don't do your homework. We prefer to help...www.freemathhelp.com
Do you have any experience finding domains? For example, are you able to find the domain of this simpler version?
\(\displaystyle \sqrt{x - x^2}\)
Also, are you familiar with the change-of-base formula for logarithms?
[imath]\;[/imath]
I DON'T THINK THIS IS HOW LOG FUNCTIONS WORK WHEN GIVEN A CONSTANT BASE.I would set the log function part greater than or equal to 0 and find the domain . Because you can only take square root of positive values.
I DON'T THINK THIS IS HOW LOG FUNCTIONS WORK WHEN GIVEN A CONSTANT BASE.
In this case I got the answer as x belongs to [0,1]You have two constraints to consider.
1) You can't take the square root of a negative number (equivalent to what you take the square root of must be >=0)
2) You can only compute the log of a positive value.
log0.4(x-x2)> 0
x-x2>0
How can x=0 be part of the domain if you want x-x2>0?In this case I got the answer as x belongs to [0,1]
Oh sorryHow can x=0 be part of the domain if you want x-x2>0?
After all, 0-02 >0 is not true!
I am sorry sir ,i just am making very silly mistakes hereHow can x=0 be part of the domain if you want x-x2>0?
After all, 0-02 >0 is not true!
x belongs to (0,1)So what is your final domain??