sum of [(1/3n+1)-(1/3n+2)] where n=0 to n= infinity
R raghvendrasingh New member Joined Dec 12, 2011 Messages 6 Dec 12, 2011 #1 sum of [(1/3n+1)-(1/3n+2)] where n=0 to n= infinity
D Deleted member 4993 Guest Dec 12, 2011 #2 raghvendrasingh said: sum of [(1/3n+1)-(1/3n+2)] where n=0 to n= infinity Click to expand... The way you wrote the problem: 1/3n + 1 -1/3n - 2 = (1/3n - 1/3n) + (1 - 2) = -1 and the problem becomes trivial. I suppose that was NOT the problem. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
raghvendrasingh said: sum of [(1/3n+1)-(1/3n+2)] where n=0 to n= infinity Click to expand... The way you wrote the problem: 1/3n + 1 -1/3n - 2 = (1/3n - 1/3n) + (1 - 2) = -1 and the problem becomes trivial. I suppose that was NOT the problem. Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.
R raghvendrasingh New member Joined Dec 12, 2011 Messages 6 Dec 14, 2011 #3 ok let me rewriteb the problem.... sum of (1/(3n+1))-(1/(3n+2)) from n=0 to n=infinity
