I am not sure How I am suppose to do this one. (4x^5y^0/z^3)^-2
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 14, 2005 #1 I am not sure How I am suppose to do this one. (4x^5y^0/z^3)^-2
D daveyp225 New member Joined Feb 24, 2005 Messages 20 Sep 14, 2005 #2 (a/b)^n = (a^n)/(b^n) (4x^5*y^0)^-2/(z^3)^-2 since y^0 = 1, you can disreguard it it should be easy from here
(a/b)^n = (a^n)/(b^n) (4x^5*y^0)^-2/(z^3)^-2 since y^0 = 1, you can disreguard it it should be easy from here
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 14, 2005 #5 ok I got this part. but I am not sure I am doing this right. I did 1024* -2 twice.(1024*-1024*-1024) I got to big of a number. what am I doing wrong?
ok I got this part. but I am not sure I am doing this right. I did 1024* -2 twice.(1024*-1024*-1024) I got to big of a number. what am I doing wrong?
G Guest Guest Sep 14, 2005 #6 (4x^5y^0/z^3)^-2 try this ..... ( 4 x^5 5 y^0 /z^3) ^-2 ((4 . 5) x^5 y^0 z^-3)) ^-2 (20 x^5 z^-3) ^-2 (1/400) x^-10 z^6 (z^6)/ (400(x^10))
(4x^5y^0/z^3)^-2 try this ..... ( 4 x^5 5 y^0 /z^3) ^-2 ((4 . 5) x^5 y^0 z^-3)) ^-2 (20 x^5 z^-3) ^-2 (1/400) x^-10 z^6 (z^6)/ (400(x^10))
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 14, 2005 #7 ( 4 x^5 5 y^0 /z^3) ^-2 I don't understand this How did you get (4 x ^5 5 y^0
G Guest Guest Sep 14, 2005 #8 ( 4 x^5 5 y^0 /z^3) ^-2 rewrite your original equation but focus on making sure the power applies to only the correct parts. (got carried away with 5's sorry) (4x^5 y^0/z^3)^-2 (4 . x^5 . y^0 /z^3) ^-2 where the . means multiply (4 . x^5 . 1. z^-3) ^-2 (1/16) (x^-10) (z^6) (z^6)/(16(x^10))
( 4 x^5 5 y^0 /z^3) ^-2 rewrite your original equation but focus on making sure the power applies to only the correct parts. (got carried away with 5's sorry) (4x^5 y^0/z^3)^-2 (4 . x^5 . y^0 /z^3) ^-2 where the . means multiply (4 . x^5 . 1. z^-3) ^-2 (1/16) (x^-10) (z^6) (z^6)/(16(x^10))
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 14, 2005 #9 You have showed me how to do this. It is still more confusing. I am still not understanding the operations.
You have showed me how to do this. It is still more confusing. I am still not understanding the operations.
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Sep 15, 2005 #10 Taking it from the top: (4x^5y^0/z^3)^-2 4x^5 = 4*x*x*x*x*x y^0 = 1 z^3 = z*z*z So you have 4*x*x*x*x*x ----------- z*z*z That is raised to the -2 power. That gives z*z*z ----------- 4*x*x*x*x*x raised to the 2 power or z*z*z*z*z*z ---------------------- 4*4*x*x*x*x*x*x*x*x*x*x Showing it in "math-speek z^6/(16x^10)
Taking it from the top: (4x^5y^0/z^3)^-2 4x^5 = 4*x*x*x*x*x y^0 = 1 z^3 = z*z*z So you have 4*x*x*x*x*x ----------- z*z*z That is raised to the -2 power. That gives z*z*z ----------- 4*x*x*x*x*x raised to the 2 power or z*z*z*z*z*z ---------------------- 4*4*x*x*x*x*x*x*x*x*x*x Showing it in "math-speek z^6/(16x^10)
L latresa31s Junior Member Joined Sep 4, 2005 Messages 135 Sep 15, 2005 #12 so how would the problem written without the extra z and x
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Sep 15, 2005 #13 Like APM did it. I was just showing them spread out. a*a*a*a = a^4