calculus

[gucci1]

i don't to how to start this problem..plz help
f(x)=(2x^1/2+1)^5(x^3+2x+1)^4 differentiate the following...

 

[Deleted member 4993]

i don't to how to start this problem..plz help
f(x)=(2x^1/2+1)^5(x^3+2x+1)^4 differentiate the following...

Use product rule and chain rule:

if

f(x) = g(x) * h(x)

then

f'(x) = g'(x) * h(x) + g(x) * h(x)

 

[lookagain]

i don't to how to start this problem..plz help
f(x)=$\displaystyle > >$(2x^1/2+1)^5(x^3+2x+1)^4 $\displaystyle < <$differentiate the following...

gucci1,

you must have grouping symbols around the first exponent (reading from from right to left). It is a fraction.

What you have is equivalent to $\displaystyle \bigg(\frac{2x^1}{2} + 1\bigg)^5(x^3 + 2x + 1)^4.$


Suggestion:

Type [2x^(1/2) + 1]^5(x^3 + 2x + 1)^4

or possibly

{[2x^(1/2) + 1]^5}(x^3 + 2x + 1)^4.


Or, use Latex:


$\displaystyle (2x^{\frac{1}{2}} + 1)^5(x^3 + 2x + 1)^4$

or possibly

$\displaystyle (2x^{1/2} + 1)^5(x^3 + 2x + 1)^4$