\(\displaystyle Given: \ log_b 2 \ = \ a \ and \ log_b 3 \ = \ c, \ find \ log_b (1728b).\)
\(\displaystyle log_b(1728b) \ = \ log_b[(2^6)(3^3)(b)] \ = \ 6log_b 2+3log_b 3+log_b b \ = \ 6a+3c+1.\)
\(\displaystyle Factor, \ factor, \ factor, \ (FTA).\)
