calculus

jas397

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Jan 1, 2006
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given tan a=2, show that sin a=2/[sqrt5] and cosa=[1/sqrt5] when o<a<pi/2
 
In case you're not provided with the fully-worked solution, please reply showing what you've tried and how far you've gotten.

You drew the right triangle in the appropriate quadrant ("o[sic] < a < pi/2") with "a" labelling the angle, you labelled the "opposite" and "adjacent" sides according to the given equivalence ("tan(a) = 2/1"), you applied the Pythagorean Theorem to find the length of the hypotenuse, and... then what?

Thank you.

Eliz.
 
jas397 said:
given tan a=2, show that sin a=2/[sqrt5] and cosa=[1/sqrt5] when o<a<pi/2

can some one solve this completely and get back to me its due 2morrow
 
jas397 said:
can some one solve this completely
"Can" we? Sure.

Will we? Not most of us, especially when you've become rather belligerant about not putting any effort of your own into this.

Eliz.
 
Why is this is a sticky? If you're desperate for answers, jas, you made it worse because now people won't be able to see this on the homepage of freemathhelp.com. This is usually how I find the most recent topics.
 
This is an odd title for a problem that is an elementary trig problem.
 
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