Calculus: Obtain the difference quotient for the function?

chess127

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Feb 16, 2009
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Can you please tell me how to obtain the difference quotient for the function f(x) = 5x^2-3x? Thank you. Is 10x + 5h - 3 the correct answer? How would you get to this answer?
 
limh05(x+h)22(x+5)(5x23x)h\displaystyle \lim_{h\to 0}\frac{5(x+h)^{2}-2(x+5)-(5x^{2}-3x)}{h}

limh010xh+5h23hh\displaystyle \lim_{h\to 0}\frac{10xh+5h^{2}-3h}{h}

limh0[10x+5h3]\displaystyle \lim_{h\to 0}[10x+5h-3]

See?. Just as you have. Now, let h=0 and you have the derivative for 5x^2-3x
 
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