Calculus Homework (vectors/forces)

sam.sim

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Hey guys I need with my calculus work.

For question A am I suppose to just mutliply 50kg/m2 x 18m x 9.8 m/s2 or do I have to use the angle in some way.

Also for question c do I just add the forces from a and b. Also how will I find the direction of the force.

Thank you for your help in advance

20191002_191638 (1).jpg
 
Thank you that's helps
So for A I would get 50kg/m2 x 18m x 9.8 m/s2 x cos 20 = 8288 N
B would be 50kg/m2 x 7m x 9.8 m/s2 x cos 60 = 1715 N
C is 1715 + 8288 = 10003

Can you please let me know if I did this correctly and what would I put for the direction for all three answers.
 
Thank you that's helps
So for A I would get 50kg/m2 x 18m x 9.8 m/s2 x cos 20 = 8288 N
B would be 50kg/m2 x 7m x 9.8 m/s2 x cos 60 = 1715 N
C is 1715 + 8288 = 10003

Can you please let me know if I did this correctly and what would I put for the direction for all three answers.
Ignore the pervious post I understand how to do it correctly now but im confused on what im suppose to do for part e.
 
Ignore the pervious post I understand how to do it correctly now but im confused on what im suppose to do for part e.
OK, so for a. it's force = mg where m is the mass of the substance, is the gravitational constant.
= 18 mts * 50 kg / m2 * 9.8 m/ sec 2
= ? Newtons. (it's not 8288)

b. = 7mts* 50 kg/m2 * 9.8 m / sec 2
= ? Newtons.(Note it's not 1715)

c. resultant force = both the forces from question a and b added together a+b=? Newtons. (note it's not 10003)

d.
f400e98dc1e233a5814c09671a366125.png

using the sine rule, we have
cramster-equation-2010471658236340625630322212503082.png

cramster-equation-2010471659246340625636433150001968.png

cramster-equation-201047172226340625654269087504534.png

now add the width of the building with the 3.5 meters = ? meters.



e. also, we get
cramster-equation-201047177586340625687894087509653.png

similarly in the other triangle,
cramster-equation-2010471711266340625708620650009705.png
2.39414mts.

it is given that B is moved 2 meters to the left.
so, EB = ?
consequently, angle at B into the first triangle ABE is now
given by ......

More then happy to help if you have any more questions.
 
Hi thank you for your help. Here is what I have so far. I just want to confirm if what I did for a and b is correct because I think I need to find the compents of the force.

For question c is this statement correct r = 428.3253 N, 22.66 clockwise from the longer angle roof.

Can you also check if I did part c and e correctly. Thank you
 

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