calculus help

[dolphin6]

The position of a particle at time t is given by s,where s^3+2st+4t^3-8t=0. find the velociy ds/dt

 

[stapel]

Differentiate implicitly, and solve for "ds/dt =".

Eliz.

 

[dolphin6]

reply

when I worked it out I got
D/dx (s^3+2st+4t^3-8t)=d/dx(0)
d/dx(s^3)+d/dx(2st)+d/dx(4t^3)+d/dx(8t)=d/dx(0)
3s^2+2s+12t+8=0
2s+12t+8=-3^2
that is where I am stuck

 

[stapel]

I'm sorry, but I don't see where "x" is coming from. You posted an equation in "s" and "t", and asked how to get "ds/dt". How does "x" relate?

Also, how are you getting that the derivative of a term in t³ is a term in t, rather than t²? Are you familiar with the Product Rule? Have you learned about implicit differentiation at all yet in class?

Thank you.

Eliz.