calculus help: limit (h -> 0) {(11-(121+h)^(1/2)}/h

[dimon]

hi

i can't solve this problem

Find limit as h --> 0 of {(11-(121+h)^(1/2)}/h

i tried to factor but wasn't able to

 

[galactus]

Multiply top and bottom by the conjugate of the numerator:

\(\displaystyle \L\\\lim_{h\to\0}\frac{11-\sqrt{121+h}}{h}\cdot\frac{11+\sqrt{121+h}}{11+\sqrt{121+h}}=\lim_{h\to\0}\frac{-h}{h(11+\sqrt{121+h})}\)

Now, finish up?.