Calculus: find limit of x - 1/x^2

[sareevan]

Find the following limits. If the limiting value is infinite, indicate whether it is +infinity x-1/x^2

 

[stapel]

Where is the limit being taken? As x approaches zero? As x tends toward infinity? Or something else?

What you have posted means the following:

. . . . .\(\displaystyle \L x\,-\,\frac{1}{x^2}\)

Is this what you meant? Or something else?

How far have you gotten on this?

Please reply with specifics, including all of your steps so far.

Thank you.

Eliz.

 

[sareevan]

calculus

Find the following limits. If the limiting value is infinte, indicate whether it is +∞ or -∞.
x-1/x^2
x→∞

The only answer that I could come up with was 0/1 Does not exist.

 

[stapel]

Okay; you've answered the question regarding what x is approaching. But we still need to know what the function actually is, and we still need to see your work.

Please reply with the answers to those queries. (We can't tell the limit to an unknown function, and we can't help you find any errors if we can't see your work.)

Thank you.

Eliz.

 

[sareevan]

calculus

(x/x^2)-(1/x^2)/(x^2/x^2) = (x-0)/1 = x/1

 

[stapel]

Re: calculus

(x/x^2)-(1/x^2)/(x^2/x^2) = (x-0)/1 = x/1

I'm sorry, but I don't know what this means, or how it relates to the question at hand.

Please reply with clarification regarding what the function is, and please show your steps clearly (line by line), so we can tell what you mean. (For instance, taking the limit as x tends toward infinity, x/1 = x would NOT tend toward 0. But this is what you say you think the limit is. Why? Please explain.)

Thank you.

Eliz.